-12x^2+22x=0

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Solution for -12x^2+22x=0 equation:



-12x^2+22x=0
a = -12; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-12)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-12}=\frac{-44}{-24} =1+5/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-12}=\frac{0}{-24} =0 $

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